Q:

Jessica is on a website that lets her build her own pizza for delivery. She has a budget of $14 (Not including tax or tip) to spend on her pizza. The pizza she wants costs $9.50 and includes 1 topping of her choice. She can also add additional toppings for $0.75 each.We have found that Jessica can model this situation using the inequality0.75(t−1)+9.50≤14 where t ≥ 1Which of the following correctly states the amount of toppings Jessica can put on her pizza.Select one:a. Jessica can have up to 8 toppings on her pizzab. Jessica can have up to 5 toppings on her pizzac. Jessica can have up to 6 toppings on her pizzad. Jessica can have up to 7 toppings on her pizza

Accepted Solution

A:
Answer:d. Jessica can have up to 7 toppings on her pizzaStep-by-step explanation:We know that the inequality that gives us the number of toppings Jessica can put on her pizza is [tex]0.75(t-1)+9.50\leq 14[/tex] where [tex]t\geq 1[/tex], so, to find the number of topics we just need to solve the inequality.Let's do it step-by-stepStep 1. Subtract 9.50 from both sides of the inequality[tex]0.75(t-1)+9.50-9.50\leq 14-9.50[/tex][tex]0.75(t-1)\leq 4.50[/tex]Step 2. Distribute 0.75 to the two terms inside the parenthesis [tex]0.75t-0.75\leq 4.50[/tex]Step 3. Add 0.75 to both sides of the inequality [tex]0.75t-0.75+0.75\leq 4.50+0.75[/tex][tex]0.75t\leq 5.25[/tex]Step 4. Divide both sides of the inequality bu 0.75[tex]\frac{0.75t}{0.75} \leq \frac{5.25}{0.75}[/tex][tex]t\leq 7[/tex]Jessica can put up to 7 topping on her pizza.We can conclude that the correct answer is d. Jessica can have up to 7 toppings on her pizza